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Hi, can somebody help me with the problem of open a popup on a specific location?

I have a toolbarbutton. When it is clicked, a popup will open.

So I tried to use getTop() and getLeft() to get x and y for the toolbarbutton. Thus I could open the popup at the location I want by adding some offset pixels.

However, the getTop() and getLeft() methods both returns null. I do not understand it. Is it supposed to work?

Is there anyway I can use to open a popup on a specific location I want? I know I could use popup.open(x,y). However this method does not take percentage as parameter. I have to give it pixel value. In this way, when browser gets resized, the the popup position will screwed.

Can somebody help? Thank You!

Hi, can somebody help me with the problem of open a popup on a specific location?position?

I have a toolbarbutton. When it is clicked, a popup will open.

So I tried to use getTop() and getLeft() to get x and y for the toolbarbutton. Thus I could open the popup at the location I want by adding some offset pixels.

However, the getTop() and getLeft() methods both returns null. I do not understand it. Is it supposed to work?

Is there anyway I can use to open a popup on a specific location I want? I know I could use popup.open(x,y). However this method does not take percentage as parameter. I have to give it pixel value. In this way, when browser gets resized, the the popup position will screwed.

Can somebody help? Thank You!