apache tiles + spring + zk ? how to load the page when menu Item is clicked ?

asked 2015-09-19 13:21:33 +0800

PRATIKKAR
3 ● 2

I am trying to load a page on click of menu . The page loading takes place through apache tiles + Spring MVC . My Menu.zul looks something likes this .

<window id="mainmenubar" apply="org.zkoss.bind.BindComposer"
        border="none"
        viewModel="@id('vm') @init('com.test.CustomWeb.VO.MenuBarVM')">
        <menubar id="mbar"
            autodrop="true"
            children="@bind(vm.nodes) @template(empty each.children?'menuitem':'menu')">
            <template name="menu" var="menu">
                <menu label="@bind(menu.name)">
                    <menupopup sclass="mymenupopup"
                        children="@bind(menu.children) @template(empty each.children?'menuitem':'menu')" />
                </menu>
            </template>
            <template name="menuitem" var="item">
                <menuitem label="@bind(item.name)"
                    onClick="@command('menuClicked',menuitem=item)" />
            </template>
        </menubar>
    </window>

and the server side handling for this is

@Command
        public void menuClicked(@BindingParam("menuitem") MenuItem ms){
           // showNotify("Clicked on "+ms.getName());
            //Executions.forward("contact.html");
            Executions.sendRedirect("contact.html");
            // TODO Auto-generated catch block
        }

But I think this is not the correct approach to do this. can some body say me a better approach