How can I open zul file from java class

answered 2013-06-11 06:53:42 +0800

JustinFrost
145 ● 1 ● 6

In your controller use something like the following:

@Listen("onClick = #buttonId")
public void openWindow(){
    //create a window
    Window window = (Window)Executions.createComponents("/path/to/zulFile.zul", null, null);
    window.doPopup();
}

answered 2013-06-18 06:46:17 +0800

nsharma
917 ● 1 ● 11

updated 2013-06-18 06:46:53 +0800

If u are using MVC model,u have to use the same way as frost suggests, the other ways is ,you can use

 <window mold="modal" ...></window>

in the Zul file you want to call,so the code in your model becomes:

Map args = new HashMap();
args.put("mapkey", variable);
    Executions.createComponents("/path/to/zulFile.zul", parentview, args);

arguments are variables you want to send to the model of the ZUL called,as parameters, In model you have to use :

@aftercompose
public void doAfterCompose(@ExecutionArgParam("mapKey") variable_type variable_name ){}

If You are using MVVM model:

In your ZUl in spreadsheet component use :

onClick="@command('onClickSpreadSheet')"

then in your viewModel write a method with same name "onClickSpreadSheet" :

@command
public void onClickSpreadSheet(){
Map args = new HashMap();
    args.put("mapkey", variable);
Executions.createComponents("/path/to/zulFile.zul", parentView, args);
}

answered 2013-06-18 07:05:26 +0800

Senthilchettyin
2623 ● 3 ● 8
http://emrpms.blogspot.in...

Some examples here