How to get the complete URL of the current page using Java

answered 2009-05-22 18:05:31 +0800

bob007
384 ● 3 ● 4

updated 2009-05-25 18:18:30 +0800

To be clearer in url like : http://www.someserver:8080/anApplication/aPage.zul?no=343&dem=aadd

I need this part http://www.someserver:8080/anApplication/aPage.zul
Or this part http://www.someserver:8080/anApplication/

I tried Executions.getCurrent().encodeURL(uri) but It dont seem to add any part to the uri

Any idea ?

Thank in advance


EDITED 25/05/2009 :
Thank you robbie its working

String port = ( Executions.getCurrent().getServerPort() == 80 ) ? "" : (":" + Executions.getCurrent().getServerPort());
url = Executions.getCurrent().getScheme() + "://" + Executions.getCurrent().getServerName() + port + Executions.getCurrent().getContextPath() +  Executions.getCurrent().getDesktop().getRequestPath();